On takeoff, the combined action of the engines and wings of an airplane exerts a(n) 7600 N force on the plane, directed upward at an angle of 60 degrees above the horizontal. The plane rises with constant velocity in the vertical direction while continuing to accelerate in the horizontal direction. That acceleration of gravity is 9.8 m/s^-2
What is the weight of the plane (in N)?
What is its horizontal acceleration m/s^-2?


Apply Newton’s 2nd law: net force = massxacceleration: ΣF = ma
F = 7600 N /_60 deg.
ΣF_y = ma_y,
but since v_y is constant, then a_y = 0,
ΣF_y = 7600 sin 60 – mg = 0,
mg = 7600 sin 60 = 7600*0.866 = 6581.8 N
Hence, the aircraft’s weight is: W = 6581.8 N
while the mass: m = W/g = 6581.8/9.81 = 671 kg
ΣF_x = 7600 cos 60 = 3800 = ma_x
a_x = 3800/671 = 5.66 m/s²